Dijkstra's Link State Algorithm
Tags: #◇CSNETWK #◇Computer Science #◇Computer Networks #◇Networking Protocols #◇Graph Theory Basics
◇Overview
Dijkstra's Algorithm is a "Link State" algorithm, meaning every router has a complete map of the network (the global topology) and identical link c...
◇Key Concepts
Source Node Goal Link Costs Distance Predecessor (p)
◇Details / Theory
◇1. Concept Overview: Link State (LS)
Definition
Dijkstra's Algorithm is a "Link State" algorithm, meaning every router has a complete map of the network (the global topology) and identical link cost information. It computes the least-cost path from a single source node to all other nodes in the network.
The Logic (Iterative)
- Initialization: The router knows the cost to its direct neighbors. All non-neighbors are set to infinity ().
- Selection: Pick the unvisited node with the smallest tentative distance.
- Relaxation: Check if going through this new node is cheaper than the current known path to its neighbors.
Formula:
◇2. The Network Topology
Dijkstra Step-by-Step Edge Relaxation Execution Loop
Resulting Shortest Path Tree (SPT) Rooted at Router U
Scenario Link Costs Summary:
- Direct Links from U:
u-v = 6,u-x = 7,u-w = 9 - Cross-Domain Links:
v-w = 8,v-x = 7,x-w = 5,x-y = 4 - Egress Links to Z:
w-z = 5,y-z = 8
◇3. Problem Analysis
Question 1
What is the shortest distance to node x and what node is its predecessor? Write your answer as n,p
Analytical Breakdown:
-
Direct Path Check: U connects directly to X with a cost of 7.
-
Alternative Path Check: Can we beat 7?
Path U V X? (Cost: ). No.
Path U V W X? (Cost: ). No. -
Conclusion: The direct link is the optimal path.
Distance: 7
Predecessor (p): The node immediately before X is u.
Correct Answer: 7,u
Question 2
What is the shortest distance to node v and what node is its predecessor? Write your answer as n,p
Analytical Breakdown:
-
Direct Path Check: U connects directly to V with a cost of 6.
-
Alternative Path Check: Can we beat 6?
Any other path (e.g., through X) would start with a cost of 7 (U X), which is already higher than 6. -
Conclusion: The direct link is the optimal path.
Distance: 6
Predecessor (p): The node immediately before V is u.
Correct Answer: 6,u
Question 3
What is the shortest distance to node z and what node is its predecessor? Write your answer as n,p
Analytical Breakdown:
This requires a multi-step search (Dijkstra's Loop).
-
Step 0 (Start): U is at 0.
-
Step 1 (Neighbors):
To V: 6 (via U)
To X: 7 (via U)
To W: 9 (via U - Note: Diagram shows a curved link u-w with cost 9) -
Step 2 (Expand V): V is cheapest (6).
V W: Cost is . (Direct path 9 is better). -
Step 3 (Expand X): X is next cheapest (7).
X W: Cost is . (Old cost 9 is better).
X Y: Cost is . -
Step 4 (Expand W): W is next cheapest (9, via U).
W Z: Cost is . -
Step 5 (Expand Y): Y is next cheapest (11, via X).
Y Z: Cost is . (Old cost 14 is better). -
Conclusion: The cheapest path to Z comes from W.
Total Cost: 14
Predecessor: w
Correct Answer: 14,w
◇Summary of Logic (Cheat Sheet)
| Destination | Cost | Predecessor | Path |
| X | 7 | u | Direct (u-x) |
| V | 6 | u | Direct (u-v) |
| Z | 14 | w | u-w-z |
Algorithm Tip: Always explore the node with the lowest current cost first.
◇Common Pitfalls
Not always expanding the cheapest unvisited node next — Dijkstra is a greedy algorithm. Forgetting to update (relax) neighbors when a cheaper path is found through the newly expanded node. Assuming the algorithm works with negative edge weights — it does not; use Bellman-Ford instead.
◇Summary
TL;DR — Dijkstra’s algorithm computes shortest paths from a source by greedily expanding the lowest-cost unvisited node and relaxing its neighbors. It requires non-negative edge weights and runs in or with a priority queue.
◇Links
Related: - ◇Pasted image 20251121093234.png Source / Reference:
◇References & Navigation
- Previous Topic: ◇Longest Prefix Matching
- Next Topic: ◇Dijkstra's Algorithm (Advanced)
- Related Notes: ◇Distance-Vector Routing and RIP, ◇Link-State Routing and OSPF
ACTIVE RECALL VERIFICATION
Select an answer to verify conceptual comprehension and reveal the technical rationale.
In a Link-State (LS) routing protocol such as OSPF, how do all routers in the network acquire the complete global network topology graph before running Dijkstra's algorithm?
In Dijkstra's algorithm initialization at source node , how are the initial distance values set for all other nodes ?
What is the worst-case time complexity of computing shortest paths from a single source across nodes using Dijkstra's algorithm: (a) with a simple linear array scan for , and (b) with a binary min-heap priority queue?
Consider a triangle graph with nodes and undirected link costs , , and . Running Dijkstra's algorithm from source , what are the final shortest-path cost and predecessor ?
How many messages are transmitted across the network to broadcast a single link-state change in a network with nodes and links?